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56x^2-12x-79=0
a = 56; b = -12; c = -79;
Δ = b2-4ac
Δ = -122-4·56·(-79)
Δ = 17840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17840}=\sqrt{16*1115}=\sqrt{16}*\sqrt{1115}=4\sqrt{1115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{1115}}{2*56}=\frac{12-4\sqrt{1115}}{112} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{1115}}{2*56}=\frac{12+4\sqrt{1115}}{112} $
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